Question

this question is from class 11​

Answer 1

Answer:

14%

Explanation:

Using relation of time-period of simple pendulum with length and gravity:

$t {}^{2} = 4 {\pi}^{2} \frac{l}{g}$

$g = 4 {\pi}^{2} \frac{l}{ {t}^{2} }$

Now,

Since 4π^2 is a constant.

Therefore

∆g % = ∆l % + 2 ∆t %

= 6 + 2×4

= 6+8 = 14

Percent error in value of g is 14%.