This question is from intensity of electricity.If you know it explain the answer in detail.No SPAM PLEASE.
Attachments:
Answers
Answered by
1
Answer:
E1=E°(2a)^2=4E°a^2----(1)
E2=E°(3a)^2=9E°a^2---(2)
(flux)1=4E°a^4
(flux)2=9E°a^4
from gauss law
((flux)2-(flux)1)=q/E•
(9E°a^4-4E°a^4)=q/E•
q=5E°a^4 E•
Similar questions