Question

this question is from projectile motion


also answer my other questions​

Answer 1

Answer:

Given : shell collides with the plane, hence;

• Horizontal motion : u cos © = 150m/sec __________1

• Vertical motion : Vertical distance travelled by the ship = vertical height of the ship ( h ).

y = ( u sin © ) t + 0.5 gt²

875 = ( u sin © ) 35 - 0.5 * 10 * 35²

875 = 35 ( u sin © - 175 )

u sin© = 25 + 175

u sin© = 200 ___________2

thus, from equation 1 and 2

( u sin © ) ² + ( u cos© )² = 200² + 150²

u² = 62500

u = 250 m/sec

also,

u sin © * 150 = 200 * u cos ©

tan © = 4/3

© = 53° ( approx )

* here I have used " © " in place of theta, due to absence of the mark in the keyboard.