Question

This question is made by me,
Given,
$\sf {x}^{2} + xy = 15$
$\sf {y}^{2} + xy = 10$
Then, find the value of x-y and x+y.
Please don't give irrelevant answers. It's my request.
It's easy. Try it. ​

Answer 1

Step-by-step explanation:

Given :-

x²+xy=15 and y²+xy=10

To find:-

find the values of x-y and x+y

Solution:-

Given equations are:

x²+xy=15-----(1)

y²+xy=10-----(2)

(+)

--------------------

x²+y²+2xy=25

---------------------

=>(x+y)²=25

=>x+y=√25

=>x+y=±5

on taking positive

x+y=5------(3)

now subtract (2) from (1)

x²+xy=15

y²+xy=10

(-)

---------------

x²-y²=5

---------------

=>x²-y²=5

=>(x+y)(x-y)=5

=>(5)(x-y)=5 (from(3))

=>(x-y)=5/5

=>x-y=1

Answer:-

x+y=5

x-y=1

Answer 2

Answer:

x+y=5

x-y=1

This is the answer