Question

THIS QUESTION IS OF 30 POINTS!

In the parallelogram ABCD, AB = 8 cm, BC = 10 cm and AE = 5 cm.


Find the height AF

WITH EXPLANATION!

the CORRECT ANSWER will get BRAINLIEST and 5 THANKS!

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Answer 1

Answer:

Given, AB=8cm;BC=4cm

Given, AB=8cm;BC=4cmPerpendicular distance between AB and BC is DL=3cm

Given, AB=8cm;BC=4cmPerpendicular distance between AB and BC is DL=3cmThe area of the parallelogram =base×height

Given, AB=8cm;BC=4cmPerpendicular distance between AB and BC is DL=3cmThe area of the parallelogram =base×height =AB×DL

Given, AB=8cm;BC=4cmPerpendicular distance between AB and BC is DL=3cmThe area of the parallelogram =base×height =AB×DL =8×3=24cm

Given, AB=8cm;BC=4cmPerpendicular distance between AB and BC is DL=3cmThe area of the parallelogram =base×height =AB×DL =8×3=24cm 2

Given, AB=8cm;BC=4cmPerpendicular distance between AB and BC is DL=3cmThe area of the parallelogram =base×height =AB×DL =8×3=24cm 2

Given, AB=8cm;BC=4cmPerpendicular distance between AB and BC is DL=3cmThe area of the parallelogram =base×height =AB×DL =8×3=24cm 2 Area of the parallelogram =base×height

Given, AB=8cm;BC=4cmPerpendicular distance between AB and BC is DL=3cmThe area of the parallelogram =base×height =AB×DL =8×3=24cm 2 Area of the parallelogram =base×height =AD×BM

Given, AB=8cm;BC=4cmPerpendicular distance between AB and BC is DL=3cmThe area of the parallelogram =base×height =AB×DL =8×3=24cm 2 Area of the parallelogram =base×height =AD×BM 24=4×height

Given, AB=8cm;BC=4cmPerpendicular distance between AB and BC is DL=3cmThe area of the parallelogram =base×height =AB×DL =8×3=24cm 2 Area of the parallelogram =base×height =AD×BM 24=4×height Height=6cm

Given, AB=8cm;BC=4cmPerpendicular distance between AB and BC is DL=3cmThe area of the parallelogram =base×height =AB×DL =8×3=24cm 2 Area of the parallelogram =base×height =AD×BM 24=4×height Height=6cmSo the perpendicular distance between AD and BC is 6cm

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