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Note:- More than one option correct.
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18
Answer :
Options : (a), (b) & (d) are correct.
Explanation :
As we all know that,
Magnetic force does not do work. From work-energy theorem :
W(Fe) = ΔK.E.
or (qE) (2a) = (1/2)m[4v^2 - v^2]
or E = (3/4)(mv^2/qa)
.°. Correct option is (a).
At P, rate of work done by electric field
= Fe . v = (qE)(v) cos0°
= q(3mv^2/4qa)v
= (3/4)(mv^2/a)
Therefore, option (b) is also correct.
Rate of work done at Q :
Electric field = Fe . v
= (qE)(2v) cos90° = 0
and of magnetic field is always zero.
Therefore , option (d) is also correct
=> Note that, Fe = qE
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