Question

This question is related to exponents and power.

Answer 1

${5}^{3} = \frac{1}{2 {}^{ n- 1} }$
${ 5}^{3} = {2}^{1 - n}$
${5}^{3} \times {2}^{0} = {5}^{0} \times {2}^{1 - n}$
uper niche ho gya hai
${5}^{3} \times 1 = {2}^{1 - n} \times 1$
${5}^{3} = {5}^{0}$
${2}^{1 - n} = {2}^{0}$
therefore
2se 2 kt gya
1-n=0
-1=-n
n=1