Question

This question is related to warli art and please reply back​

Answer 1

Answer:

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Answer 2

Given:-

• ΔRPQ and ΔRST are congruent.

• Base of a triangle is 4 cm and Height is 5 cm.

• Radius of Circular head is 0.7 cm.

To FInd:-

• The Total Area of the Figure.

Solution:-

Here, The ΔRPQ and ΔRST are congruent so there measurement will be equal.

So, Area of ΔRPQ ⇒ $\dfrac{1}{2}$ × base × height

                              ⇒ $\dfrac{1}{2}$ × 4 × 5 cm²

                              ⇒ 10 cm²

Now, Area of Circular head ⇒ πr²

                                              ⇒ $\dfrac{22}{7}$ × 0.7 × 0.7

                                              ⇒ 1.54 cm²

So, Area of the given figure ⇒ 2 × ( Area of ΔRPQ ) + Area of circular head

                                              ⇒ 2 × 10 cm² + 1.54 cm²

                                              ⇒ 21.54 cm²

Hence, Area of the figure is 21.54 cm².

Some important terms:-

• Circumference  of the circle = 2πr

• Area of Equilateral triangle = $\dfrac{\sqrt{3}}{4}$ × Side²

• Height of Equilateral triangle = $\dfrac{\sqrt{3}}{2}$ × side

• Heron's Formula = $\sqrt{s ( s - a) (s - b) (s - c)}$    where, S = $\dfrac{a + b + c}{2}$