this question is tricky from the lesson comparing quantities . please help me to solve these questions
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S.p of 1st buffalo= Rs 20000
gain= 5%
C.p= 105/100×20000=Rs 21000
then,
S.p of 2nd buffalo=Rs 20000
Loss%= 10%
C.p= 90/100×20000=Rs 18000
then,
S.p of both the buffaloes=Rs 20000+20000= 40000
C.p of both the boffaloes= Rs39000
loss=Rs 40000-39000=1000
loss% = 1000/40000×100%=2.5%
hence, the milkman made a loss of 2.5%
Hope!! it helped
gain= 5%
C.p= 105/100×20000=Rs 21000
then,
S.p of 2nd buffalo=Rs 20000
Loss%= 10%
C.p= 90/100×20000=Rs 18000
then,
S.p of both the buffaloes=Rs 20000+20000= 40000
C.p of both the boffaloes= Rs39000
loss=Rs 40000-39000=1000
loss% = 1000/40000×100%=2.5%
hence, the milkman made a loss of 2.5%
Hope!! it helped
shiva198:
but the ans is loss of rs 1,269.84
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