Math, asked by afgr, 1 year ago

this question is trigonometry

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Answered by Anonymous

Given : <A, <B and <C are the three interior angles of a triangle.

So, we can say :

<A + <B + <C = 180°

Or, <B + <C = 180° - <A

(i) sin [(B+C)/2]

= sin [(180°-A)/2]

= sin (90° - A/2)

= cos A/2 [SHOWED]

(ii) <B + <C = 180° - <A

Or, <B + <C = 180° - 90°

Or, <B + <C = 90°

Now, tan [(B+C)/2]

= tan [90°/2]

= tan 45°

= 1 [ANSWER]

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Answered by Uniquedosti00017

Answer:

the solution is in the attachment.

$..$

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