Question

this question is unsolved​

Answer 1

Step-by-step explanation:

ABC and DBC are two isosceles triangle with common base BC

In ∆ABC and ∆ACD

AB = AC

BD = CD

AD = AD

∆ABC = ∆ACD (SSS congruence rule)

:angle BAE =angle CAE. (C.P.C.T)

In ∆ABE = ∆CAE

AB = AC;

: angle BAE = angle CAE,

AE=AE

∆ABE = ∆ACE. (SSS congruence rule)

:angleBEA =angle CAE and BE = EC. (CPCT)

angle BEA =angle CEA=180° ( linear pair)

2angle BEA =180°

=angle BEA =90°

angle BEA = 90°= angle CEA

hence proved.

Answer 2

Step-by-step explanation:

thanks for free points....