Math, asked by palnitish946, 7 months ago

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Answered by Itznikhilhere
3

\huge\mathfrak\red{YOUR ANSWER}

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Answered by anandgeetha2302
0

ANSWER:

X^3-Y^3=[X-Y]{X^2+XY+Y^2]

             ={X*X^2+XY+Y^2]-[Y*Y^2+XY+X^2]

             =[X^3++X^2Y+XY^2]-[Y^3+XY^2+X^2Y}{COMMON VARIABLES TO BE CUT}

X^3-y^3 =X^3-Y^3

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