Question

this question please answer to this question ​

Answer 1

Answer:

Step-by-step explanation:

Answer 2

we know that,

${a}^{x} = {k}^{m} \\ taking \: log \: both \: sides\\ x log(a) = m log(k) \\x = \frac{m log(k) }{ log(a) } \: \: \: ...(1) \\ \\ {( \frac{a}{k} )}^{y} = {k}^{m} \\ taking \: log \: both \: sides \\ y log( \frac{a}{k} ) = m log(k) \\ y = \: \frac{m log(k) }{ log( \frac{a}{k} ) } \: \: \: ...(2) \\ \\ therefore \\ \frac{1}{x} - \frac{1}{y} = \frac{ log(a) }{m log(k) } - \frac{ log( \frac{a}{k} ) }{m log(k) } \: \: \: (from \: 1. \: and \: 2.) \\ = \frac{ log( \frac{a}{ \frac{a}{k} } ) }{m log(k) } \: \: (using \: log(m) - log(n) = log( \frac{m}{n} ) ) \\ = \frac{ log(k) }{m log(k) } = \frac{1}{m} \\ \\ hence \\ \frac{1}{x} - \frac{1}{y} = \frac{1}{m}$