Question

This question please fast in 7 mins❤​

Answer 1

Answer:

b)

this is correct 110000009% sure.

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Answer 2

Explanation:

Velocity of the particle executing SHM at any ins_tant is defined as the time rate of change of its displacement at that ins_tant.

Let the displacement of the particle at an ins_tant t is given by

x = a sinωt

∴ Velocity v = dx / dt = d ( a sinωt ) / dt

= aωcos ωt = aω √ ( 1 - sin^2 ωt )

= aω √ [ 1 - ( x^2 / a^2) ] = ω √ ( a^2 - x^2 )

At mean positon, x = 0

∴ vmax = ωa

According to problem,

v = vmax /2 = aω / 2

But v = ω √ a^2 - x^2

∴ aω / 2 = ω √( a^2 - x^2 ) or x = √3 / 2 a

∴ Option b is the correct answer !