this question pleaseee
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refer the pic
answer is A)a:b..
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Answer:
Area of ABFE : Area of EFCD :: (3a + b) : (a + 3b)
Step-by-step explanation:
AB = a cm
CD = b cm
E & F mid point
=> EF ║ AB ║ DC
& EF = (AB + DC)/2 = (a + b)/2
Area of ABFE = (1/2) ( a + (a +b/2)) = (1/4) (3a + b)
Area of EFCD = (1/2) ( (a +b/2) + b) = (1/4) (a + 3b)
=> Area of ABFE : Area of EFCD :: (1/4) (3a + b) : (1/4) (a + 3b)
=> Area of ABFE : Area of EFCD :: (3a + b) : (a + 3b)
option B is correct
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