Question

This question requires to find x
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Answer 1

Given:-

• $\sf{\angle{BAC} = x}$, $\sf{\angle{ACB} = 3y}$, $\sf{\angle{ABC} = 5y}$ and $\sf{CBD} = 2y}$.

To Find:-

• Find X.

CONCEPT USED:-

• Corresponding angle.

• Angle Sum Property

Now,

$\implies\sf{ \angle{CAB} = \angle{CBD} = 2y^{\circ}}$ ( Corresponding angle )

Therefore,

$\implies\sf{\angle{BAC} + \angle{ABC} + \angle{ACB} = 180^{\circ}}$

$\implie\sf{ 3y + 2y + 5y = 180^{\circ}}$

$\implies\sf{ 12y = 180 }$

$\implies\sf{ y = \dfrac{180}{12}}$

$\implies\sf{ y = 15}$.

So, The Value of y is 15°.

Hence,

$\implies\sf{ \angle{CAB} = \angle{CBD} = 2y^{\circ}}$ ( Corresponding angle )

$\implies\sf { x = 2y}$

$\implies\sf{ x = 2\times{15} = 30}$.

So, The Value of x is 30°