Question

This question was asked in upsc can anybody answer it give it a try 5 - 4 = 23. 8 - 1 = 63. 6 -16 = 32 9 - 9 = 78 3 - 9 = 6 3 - 81 = ? Explain the logic. Challenge for all masterminds!!

Answer 1

$<b><i>$Given -

5 - 4 = 23

Step 1. Squaring of 5 = (5)² = 25

Step 2. Square root of 4 = √4 = 2

Step 3. Subtract both the result = 25 - 2 = 23



8 - 1 = 63

Step 1. Squaring of 8 = (8)² = 64

Step 2. Square root of 1 = √1 = 1

Step 3. Subtract both the result = 64 - 1 = 63



6 - 16 = 32

Step 1. Squaring of 6 = (6)² = 36

Step 2. Square root of 16 = √16 = 4

Step 3. Subtract both the result = 36 - 4 = 32




9 - 9 = 78

Step 1. Squaring of 9 = (9)² = 81

Step 2. Square root of 9 = √9 = 3

Step 3. Subtract both the result = 81 - 3 = 78




3 - 9 = 6

Step 1. Squaring of 3 = (3)² = 9

Step 2. Square root of 9 = √9 = 3

Step 3. Subtract both the result = 9 - 3 = 6



Similarly,



3 - 81 = ?

Step 1. Squaring of 3 = (3)² = 9

Step 2. Square root of 81 = √81 = 9

Step 3. Subtract both the result = 9 - 9 = 0




$\huge\mathsf\red{\boxed{3 - 81 \ = \ 0}}$

Answer 2

Answer:

0

Step-by-step explanation:

Given

5 - 4 = 23. 8 - 1 = 63. 6 -16 = 32 9 - 9 = 78 3 - 9 = 6 3 - 81 = ?

The logic we can apply to this is square of the number minus square root of the number.

  So square(no) - square root(no)

     5 - 4 = 5 ^2 - √4

             = 25 - 2 = 23

     8 - 1 = 8 ^2 - √1

             = 64 - 1 = 63

     6 - 16 = 6 ^2 - √16

               = 36 - 4 = 32

    9 - 9 = 9 ^2 - √9

              = 81 - 3 = 78

   3 - 9 = 3 ^2 - √9

             = 9 - 3 = 6

   3 - 81 = 3 ^2 - √81

              = 9 - 9 = 0

So the answer is 0