Chemistry, asked by olivarjocelyn21, 1 day ago

This reaction is used to obtain iron from iron ore Fe₂O₂ (s) + 3 COcg) → 2 Fecs) + 3 CO2 (g) The reaction of 185g of Fez Og with 95.8 g of co Produces 87. 4 g Fe. Find the limiting reactant, theoretical yield, and percent yield?​

Answers

Answered by pathilakshmi871
0

Answer:

photo ncluear reaction da thambi

Answered by vindobhawe
2

Explanation:

Balance reaction:

Fe₂O₃ + 3CO → 2Fe +  3CO₂

185 g Fe₂O₃ × 1 mol Fe₂O₃/ 159.69 g Fe₂O₃ × 3 mole CO/ 1 mole Fe₂O₃ × 28 g / 1 mol CO =

                    = 1.15 × 3 × 28

                    = 96.6 g of CO since we have 95.8, Fe₂O₃ is the limiting agent.

185 g Fe₂O₃ × 1 mol Fe₂O₃/ 159.69 g Fe₂O₃ × 2 mole Fe / 1 mole Fe₂O₃ × 55.84 g / 1 mol Fe =

                              = 1.15 × 2 × 55.84

                              =128.43 g of Fe

Theorectical yield

185 g Fe₂O₃ ⇒ 87.4 g of Fe

If 87.4 g of Fe is formed in the reaction then the % yield will be

                                  = 87.4 g of Fe/128.43 g of Fe × 100

                                  = 68.05 %

                           

                                                                         

Similar questions