Question

This rectangular block contains 64 smaller blocks. If one small block is removed from each corner of the large block above, how many would be left? ​

Answer 1

Given : This rectangular block contains 64 smaller blocks.

one small block is removed from each corner of the large block

To Find :   how many would be left  

Solution:

rectangular block contains 64 smaller blocks.

64 = 1 * 1 * 64

will have only two corners

Hence left = 64 - 2 = 62  blocks

rectangular block contains 64 smaller blocks.

64 = 1 * ( l * b)      l * b = 64  but l , b  ≠ 1  ( can be be 2*32 , 4 * 16 , 8 * 8)

will have  four corners

Hence left = 64 - 4 = 60  blocks

rectangular block contains 64 smaller blocks.

64  = lbh  , l, b & h ≠ 1

can be 2 * 2 * 16  ,  2 * 4 * 8  ,  4 * 4 * 4  

Then it will have 8 corners

Hence left = 64 - 8 = 56  blocks

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