Question

this side of a rectangular park are in the ratio 4:3. if its area is 2028 sq.m. find the cost of fencing it at 3 Rupee's per meter.

Answer 1

Hello...
Answer...

Given :-
The side of a rectangular park are in the ratio 4:3
Area = 2028m²

Let,
length = 4x
breadth = 3x

Area = 2028
=> length×breadth = 2028
=> 4x × 3x = 2028
=> 12x² = 2028
=> x² = 2028÷12
=> x² = 169
=> x = √169
=> x = 13

length = 4x = 4×13 = 52m
breadth = 3x = 3×13 = 39m

Perimeter of the rectangle
= 2(length+breadth)
= 2(52+39)
= 2(91)
= 2×91
= 182

Perimeter = 182 m

If the cost of fencing the it per m = ₹ 3
Than,
the cost of fencing the rectangular park = 3×182 = ₹ 546

Hope it helped
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Answer 2

Given :-
The side of a rectangular park are in the ratio 4:3
Area = 2028m²

Let,
length = 4x
breadth = 3x

Area = 2028
➡ length*breadth = 2028
➡ 4x × 3x = 2028
➡ 12x² = 2028
➡ x² = 2028/12
➡ x² = 169
➡ x = √169
➡ x = 13

length = 4x = 4*13 = 52m
breadth = 3x = 3*13 = 39m


Perimeter of the rectangle
= 2(length+breadth)
= 2(52+39)
= 2(91)
= 2*91
= 182

Perimeter = 182 m

If the cost of fencing the it per m = ₹ 3
Than,
the cost of fencing the rectangular park = 3*182 = ₹ 546