Question

this spring extends by X on loading the energy stored by a spring is​

Answer 1

Explanation:

Potential energy stored

$= \frac{1}{2} m{(omega})^{2} {x}^{2} {a}^{2}$

Kinetic energy

$= \frac{1}{2} m {(omega)}^{2} ( {a}^{2} - {x}^{2} )$

Total energy = potential energy- kinetic energy

$= \frac{1}{2} m{(omega})^{2} {x}^{2} {a}^{2}$

Hope it helps.