Question

this the question...........
answer me

Answer 1

Solution:-
(I) for first car,
u= 15m/s
v= 0
a= - 3m/s²
Now,
distance travelled by First car when come to rest is( using 3rd equation of motion)

v² = u². +2as
0 = 15² + 2*(-3)*s
0 = 15² - 6s
6s= 15×15
s=37.5m

(ii) for second car,
u= 16m/s
v= 0
a= - 4m/s²
Now,
distance travelled by second car when come to rest is( using 3rd equation of motion)

v² = u². +2as
0 = 16² + 2*(-4)*s
0 = 16² - 8s
8s= 16×16
s= 32m
Now ,
they are apart 150m before' coming to rest
So,
distance between them after rest,
= 150- (32 +37.5)
= 150 - 72.5
= 77.5m
Note:- Given options are incorrect