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Explanation:
1. equivalent resistance of 6 and 12 is
( 6 x 12 ) /18 = 4ohm.
2.I = E / R = 24 /( 4 + 8) = 24 / 12 = 2 A
3. pd across parallel network
V = I x R( equivalent) = 2 x 4 = 8V
4. pd across parallel network is same
I¹ x 6 = I² x 12
I¹/ I² = 2
I = I¹ + I² = 2
I²( I¹/I² + 1) = 2
I² ( 3) = 2
I² = 2/3
I¹ = I² x 2 = 4/3A
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