Question

This verify question please...........fast

Answer 1

Question

Verify :-

• (x -y)² = x² - 2xy + y² , For x = 4 , y = 1

Prove

First Take L.H.S.

(X - Y )²

keep value of x & y

= ( 4 - 1 )²

= (3)²

= 3 × 3

= 9

Now, Take R.H.S.

( X² - 2XY + Y²)

Keep value of x & y

= (4² - 2 × 4 × 1 + 1²)

= (16 - 8 + 1)

= 17 - 8

= 9

Here,

L.H.S. = R.H.S.

So, This identity Verified for x = 4 & y = 1

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Answer 2

Step-by-step explanation:

Given:

• Equation = ( x – y )² = x² – 2xy + y²
• Values = x = 4 & y = 1

To Prove:

• LHS = RHS

Proof: Putting the values of x & y in LHS.

• Using (a – b)² = a² + b² –2ab

$\implies{\rm }$ ( x – y )²

$\implies{\rm }$ ( 4 – 1 )²

$\implies{\rm }$ ( 4 )² + ( 1 )² – 2 x 4 x 1

$\implies{\rm }$ 16 + 1 – 8

$\implies{\rm }$ 17 – 8

$\implies{\rm }$ 9

➟ Now, put the values of x & y in RHS.

$\implies{\rm }$ x²– 2xy + y²

$\implies{\rm }$ ( 4 )² – 2 x 4 x 1 + ( 1 )²

$\implies{\rm }$ 16 – 8 + 1

$\implies{\rm }$ 17 – 8

$\implies{\rm }$ 9

Hence, LHS = RHS, Thus verified !

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★ Some other identities ★

➪ ( a + b )² = a² + 2ab + b²

➪ a² – b² = ( a + b ) ( a – b )

➪ ( x + a ) ( x + b ) = x² + ( a + b )x + ab

➪ ( a + b + c )² = a² + b² + c² + 2ab + 2bc + 2ca