Thita is angle between side CA and CB of triangle shown in the figure then thita is given by.?
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where is the figure of triangle
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Answer:
The angle θ is given by cos⁻¹(2/3).
Explanation:
Given,
The side AB is 3m.
The side BC is 3m.
The side CA is 4m.
θ is the angle between the sides CA and CB.
To find,
The value of the angle θ.
Calculation,
From observation the triangle ABC is an isosceles triangle.
Let's drop a perpendicular from point B onto the side CA at D. Then the length of the side CD is 2m as it is an isosceles triangle.
Now from triangle BDC
cos(θ) = adjacent side/hypotenuse side
⇒ cos(θ) = CD/CB
⇒ cos(θ) = 2/3
⇒ θ = cos⁻¹(2/3)
Therefore, the angle θ is given by cos⁻¹(2/3).
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