Physics, asked by shubhangisambhoj, 1 year ago

Thita is angle between side CA and CB of triangle shown in the figure then thita is given by.?

Answers

Answered by Anonymous
2

Answer:

where is the figure of triangle

Answered by rishkrith123
0

Answer:

The angle θ is given by cos⁻¹(2/3).

Explanation:

Given,

The side AB is 3m.

The side BC is 3m.

The side CA is 4m.

θ is the angle between the sides CA and CB.

To find,

The value of the angle θ.

Calculation,

From observation the triangle ABC is an isosceles triangle.

Let's drop a perpendicular from point B onto the side CA at D. Then the length of the side CD is 2m as it is an isosceles triangle.

Now from triangle BDC

cos(θ) = adjacent side/hypotenuse side

⇒ cos(θ) = CD/CB

⇒ cos(θ) = 2/3

⇒ θ = cos⁻¹(2/3)

Therefore, the angle θ is given by cos⁻¹(2/3).

#SPJ2

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