Question

Tho first three terms or an AP are respectively (3y-1),(3y+5) and
(5y+1), find the value ofy.

Answer 1

Answer:

y=5

Step-by-step explanation:

If a, b, c are three terms of an AP then

b-a=c-b

Using the above

$(3y + 5 )- (3y - 1) = (5y + 1) - (3y + 5)$

$6 = 2y - 4$

$2y = 10$

$y = 5$