Thomas gave 3/7 marbles to his friends. He gave 3/5 of the remaining marbles to his brother. His cousin then gives him another 434 marbles. In the end, he had twice as many marbles he had at first. How many marbles did Thomas have at first?
Answers
Answered by
1
Answer:
245
Step-by-step explanation:
let the marbles he had be x
he gave 3/7
=x-3x/7
=7x-3x/7 = 4x/7
then he gave 3/5
=4x/7 - 3 (4x)/5 (7)
=4x/7 - 12x/35
=20x - 12x/35
=8x/35
his friend gave 435 marbles
=8x/35 + 435
he had double marbles than first
=2x
8x/35 + 435 = 2x
8x-70x/35= -435
-62x = -15190
x = -15190/-62
x = 245
Answered by
0
Answer:
K
Step-by-step explanation:
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