Question

those who answer I will mark as brain est ​

Answer 1

Answer:

P(A∪B)=P(A)+P(B)−P(A∩B)

A∩B=∅ :

P(A∪B)=P(A)+P(B)

Since A and B are disjoint sets, P(A)=P(A−B) and P(B)=P(B−A), so

P(A∪B)=P(A)+P(B)=P(A−B)+P(B−A)

P(A−B)+P(B−A)=P(A)+P(B)−P(A∩B)

P(A∪B)=P(A)+P(B)−P(A∩B)

hence proved.

Step-by-step explanation: