Question

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Answer 1

Answer:

1=0.675

2=0.66

3=0.135

4=0.985

5=0.015

Step-by-step explanation:

PROBABILITY OF THE EVENT =NO. OF FAVOURABLE OUTCOMES/TOTAL NO. OF OUTCOMES

TOTAL NO OF EVENTS =200

1.the probability of getting the person more than or equal to 40 years are=86+46+3=135

total no. of events =200

probability of event =135/200

=0.675

2.the probability of getting person under 60 years but over 39 years=86+46=132

total no of events=200

probability of event =132/200

=0.66

3.probability of getting person having age from30 to 39 years=27

total no. of events =200

probability of event =27/200

=0.135

4.probability of getting person atmost 59 years=197

total no of events =200

probability of event =197/200

=0.985

5.the probability of getting person atleast 60 years=3

total no of events =200

probability of event =3/200

=0.015

Answer 2

$\huge\star{\red{Q}{uestion}}\star\:$

Sum of the digits of a two-digit number is 12. The given number exceeds the number obtained by interchanging the digits by 36. Find the given

number.

$\huge\star{\red {A}{nswer}}\star\:$

$\huge\underline {Let,}$

The tens digit of the required number be x

and the units digit be y

$\huge\underline {Then,}$

x + y = 12 ......... eq. (1)

Required number = (10x + y)

Number obtained on reversing the digits = (10y + x)

$\huge\underline {Therefore,}$

(10y + x) - (10x + y) = 18

9y - 9x = 18

x - y = 12 ......... eq. (2)<br>

On adding eq. (1) and eq. (2)

$\huge\underline {We\: get}$

x + y + y - x = 12 +2

2y = 14

y = 2

$\huge\underline {Therefore}$

x = 5

Hence, the required number is 57

$\huge\green { Hope\: this\: helps\: you}$

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