Question

THOSE WHO CAN I WULL SALUTE THEM YAR
ITS A TUFF QUESTION
#help by solving

Answer 1

sorry I didn't solve this

Answer 2

according to this equation

x - p = 0; x = p

and hence on putting this value in the both equation

$p(x) = (p)^3 + 4(p)^2 - 2p + 1$

$0 = p^3 + 4p^2 - 2p + 1$ (¡)

and in the second equation

$p(x) = (p)^3 + 3(p)^2 - p + 7$

$0 = p^3 + 3p^2 - p + 7$ (¡¡)

so according to (¡) and (¡¡)

$p^3 + 4p^2 - 2p + 1 = p^3 + 3p^2 - p + 7$

$p^3 - p^3 + 4p^2 - 3p^2 - 2p + p + 1 - 7 = 0$

$p^2 - p - 6 = 0$

$p^2 - 3p + 2p - 6 = 0$

$p(p - 3) + 2(p - 3)$

$(p + 2) ( p - 3)$

so the values of p are

p + 2 = 0 ; p = -2

p - 3 = 0 ; p = 3