Question

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this is a question

Factorise the following

1)
$12 {x}^{2} - 7x + 1$
2)
$2 {x}^{2} + 7x + 3$
3)
$6 {x}^{2} + 5x - 6$
​

Answer 1

Answer:

1) (4x-1)(3x-1)

2)(2x+3)(x+3)

3) (2x+3)(3x-2)

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Answer 2

Answer:

Step-by-step explanation:

so for the first one it is

12x^2-7x+1

so u transfer the 12 to 1 so u will get

ab=12 a+b=7

4 and 3 can be a and b respectively so u answer will be

12x^2-4x-3x+1

4x(3x-1)+1(-3x+1)

take - common u will get

(4x-1)(3x-1)

2nd one

2x^2+7x+3

transfer 2 to 3

u will get

ab=6 and a+b=7

the perfect number for them r 6 and 1 respectively

so

2x^2+6x+x+3

2x(x+3)+1(x+3)

(2x+1)(x+3)

third one

6x^2+5x-6

transfer 6 to -6

u will get

ab=-36 and a+b=5

the perfect number for them r  4 and 9 respectively

so

6x^2+9x-4x-6

3x(2x+3)-2(2x+3)

(3x-2)(2x+3)

i really hope this helps u

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