(those who will answer it i will mark as brainliest) In the given figure, AD ⊥ BC, AD ⊥ EF and ∠EAB = ∠FAC. Prove that ∆ ABD ≅ ∆ ACD.
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arsh642
14.01.2020
Social Sciences
Secondary School
+15 pts
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In the figure alongside, AD ⊥ BC, AD ⊥ EF and ∠1 = ∠4. Prove that ∆ ≅∆ ABD ACD.

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Yashg203
Ambitious
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277 people helped
Answer:
given = AD perpendicular to BC as well as EF
angle 1 = angle 4
To prove = Triangles ABD and ACD are congruent
proof = in triangle ABD and ACD
as AD is perpendicular to EF
it simplies that angle DAF = DAE {Each 90 degree}
so subtracting equal angles that is angle 1 and angle 2 from angle DAF and DAE
=angle 2 = angle 3. (ANGLE)
AD = AD. (COMMON SIDE)
angle ADB=angle ADC (Given)
hence both triangles are congruent by ASA congruency rule
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