Question

(Those who will answer this question correctly I will mark as brainliest, thank and rate ur answer and wrong answer will be reported) \frac{p-2}{3}-\frac{p-3}{2}-\frac{p-1}{4}=0

Answer 1

Answer:

p = $\frac{13}{5}$

Step-by-step explanation:

$\frac{p-2}{3}-\frac{p-3}{2}-\frac{p-1}{4}= 0$

taking LCM of denominators as 12

$4(\frac{p-2}{12})-6(\frac{p-3}{12})-3(\frac{p-1}{12})= 0$

As 12 is common hence taking it to other side, we are left with :

4p - 8 - 6p +18 -3p + 3 = 0

-5p + 13 = 0

p = $\frac{13}{5}$

Answer 2

Answer:

$\huge{\boxed{\rm{\red{p=13/5}}}}$

Step-by-step explanation:

Given that:-

(p-2)/3-(p-3)/2-(p-1)/4=0

LCM of 3,2,4 is 12

=>{4(p-2)-6(p-3)-3(p-1)}/12=0

=>{(4p-8)-(6p-18)-(3p-3)}/12=0

=>(4p-8-6p+18-3p+3)/12=0

=>(-5p+13)/12=0

=>-5p+13=0×12

=>-5p+13=0

=>-5p=-13

=>p=-13/-5

=>p=13/5

The value of p is 13/5