Question

though substitution methodTwo years ago, a father was five times as old as his son. Two years later, his age will be 8 more than three times the age of the son. Find the present ages of Father & Son.​

Answer 1

Answer:

let father's age be x and sons age be y

$x - 2 = 5(y - 2) \\ x - 2 = 5y - 10 \\ = x + 8 = 5y \\ x + 2 = 8 + 3y \\ x = 6 + 3y \\ subtracting \: both \: the \: equations \: \\ x + 8 - x = 5y - 6 - 3y \\ 8 = 2y - 6 \\ y= 7 \\ x = 6 + 3 \times 7 \\ x = 6 + 21 \\ x = 27$

the age of father ans son is 27 and 7 years