Question

Thr amount of electricity required to produce 12.7 g of copper from cuso4

Answer 1

Answer:

First of all, write the half cell reaction:

Cu^{+2}+2e^{-}\rightarrow CuCu

+2

+2e

−

→Cu

Now, we can see that :

For 63.5 gram of Cu, we need 2 moles (or 2 F) electricity.

So, for 12.7 gram of Cu , we need :

= \dfrac{2}{63.5} \times 12.7=

63.5

2

×12.7

= 0.4 \: F=0.4F

So, 0.4 F of electricity is necessary.

In terms of Coulomb, we can say:

\implies 0.4 \: F \approx 0.4 \times 96500 = 38600 \: C⟹0.4F≈0.4×96500=38600C

So, 38600 Coulomb of electricity is necessary.