Question

thr angle of a triangle are in AP whose common difference is 20 degree find the angles ​

Answer 1

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Answer 2

Answer:

Given: The angles of quadrilateral are in A.P. where common difference (d) = 10°

Let the smallest angle be a.

Then the other angles will be a + 10, a + 20 and a + 30

we know that sum of angles of quadrilateral is 360°

⇒ a + (a +10) + (a + 20) + (a + 30) = 360

⇒ 4a + 60 = 360

⇒ 4a = 360 – 60 = 300

Hence the angles are

75°, (75 + 10)°, (75 + 20)° and (75 + 30)°

= 75°, 85°, 95° and 105°