Question

thr present age of the father exceeds that of his son by 20 years. twenty years ago,the age of the father was five times that of his son. find the present age​

Answer 1

Answer:

45 years and 25 years

Step-by-step explanation:

Father's Present Age = x

Son's Present Age = x - 20

20 years ago,

father's Age = x -20

Son's Age = x - 20-20 = x-40

father's age = 5(son's age)

x-20 = 5(x-40)

x-20 = 5x-200

-20+200=5x-x

180 = 4x

x= 180/4

x=45 years (father's present age)

x-20=25 years (son's present age)

Answer 2

Answer:

age of son x

age of father x+20

before twenty years

age of son x-20

age of father x+20-20

x=5(x-20)

x=5x-100

100=5x-x

100=4x

x=100/4

x=25

age of son 25

age of father =20+25=45