thr side of a triangle in ratio 5ratio12ratio13 and its perimeter is 150m.find the area of triangle
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ratio of sides of the triangle- 5:12:13.
let the sides be 5x, 12x,13x
perimeter = 150 m
》 5x + 12x + 13x = 150
》30x = 150
》 x = 5
5x = 5(5) = 25 m
12x = 12 ( 5) = 60m
13x = 13(5) = 65 m.
therefore, the sides of the triangle are 25m, 60m,65m.
Here; 25,60,65 are pythogras triplets.
( 25 square + 60 square = 65 square )
》 the triangle with sides 25m, 60m, 65 m forms a right angled triangle.
base = 60m ; height = 25m.
area of triangle = 1/2 × base × height = 1/2 × 60 × 25 = 750 sq.m.
( or )
let a = 25m ; b = 60m ; c = 65cm
s = a+b+c /2. = 25+60+65 /2 = 150/2 = 75.
Now substitute these values in heron's formula to find area of the triangle.
Heron's formula =
after solving using this formula u get the same answer 750 sq.m.
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