Question

thr sum of present age of a man and his son is 45 years. 5 years ago product of their ages was 4 time that of age of man. Find their present age. ​

Answer 1

Let the present age of the son be x years Given that, sum of present ages of man and his son is 45 years. ⇒ Man’s present age = (45 – x)years And also given that, five years ago, the product of their ages was four times the man’s age at the time. ⇒ Man’s age before 5 years = (45 – x – 5) years = (40 – x) years And son’s age before 5 years = (x – 5) years But, given that (40 – x) (x – 5) = 4(40 – x) ⇒ x – 5 = 4 ⇒ x = 9 years ⇒ Son’s present age ⇒ x = 9 years Now, Man’s present age ⇒ (45 – x) years = (45 – 9) years =36 years ∴ The present ages of man and son are 36 years and 9 years respectively.

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