Thr sum of three consecutive multiples of 5 is 945 find the largest multiple
Answers
Answered by
0
Hi friend!!
Let the three consecutive multiples of 5 be 5x,5x+5,5x+10
Their sum =945
5x+5x+5+5x+10=945
15x+15=945
15x=930
x=62
So, the largest number is 5x+10=5(62)+10
=310+10=320
I hope this will help you ;)
Let the three consecutive multiples of 5 be 5x,5x+5,5x+10
Their sum =945
5x+5x+5+5x+10=945
15x+15=945
15x=930
x=62
So, the largest number is 5x+10=5(62)+10
=310+10=320
I hope this will help you ;)
Answered by
0
heya....
your answer is:
5x+5x+5+5x+10 = 945
15x+15 = 945
15x = 945-15
15x = 930
x = 930/15
x = 62.
The largest multiple = 5x+10 = 5 (62) +10 = 310 +10 = 320.
It may help you...☺☺
your answer is:
5x+5x+5+5x+10 = 945
15x+15 = 945
15x = 945-15
15x = 930
x = 930/15
x = 62.
The largest multiple = 5x+10 = 5 (62) +10 = 310 +10 = 320.
It may help you...☺☺
Similar questions
History,
8 months ago
English,
8 months ago
Computer Science,
8 months ago
Social Sciences,
1 year ago