Three 2 ohm resistors, A, B and C are connected( 1 in series and 2 in parallel). Each of them dissipates energy and can withstand a maximum power of 18W without melting. Find the maximum current that can flow through the three resistors.
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Resistance B and C are connected in parallel then their resultant resistance is series with resistance A.all over resultant would be
1/Req=1/Rb+1/Rc
1/Req=1/2+1/2
Req=1Ω
This equivalent is series with A resistance
Rnet=Req+R(A)
Rnet=2+1=3Ω
As power=(Current)² Resistance
18=I²X3
I²=6 ,I=√6
I=2.2A current
Resistance B and C are connected in parallel then their resultant resistance is series with resistance A.all over resultant would be
1/Req=1/Rb+1/Rc
1/Req=1/2+1/2
Req=1Ω
This equivalent is series with A resistance
Rnet=Req+R(A)
Rnet=2+1=3Ω
As power=(Current)² Resistance
18=I²X3
I²=6 ,I=√6
I=2.2A current
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20
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