Question

Three 2 ohm resistors are connected to form a triangle .the resistance between any two corners is

Answer 1

so other 2 resistors are in series...= 2+2 = 4ohms

this 4ohm resistor will be parallel with 2 ohm resistor = 8/6= 1.33 ohms.

Answer 2

Answer:

Equivalent resistance, R = 1.34 ohms

Explanation:

It is given that, three 2 ohm resistors are connected to form a triangle. So, arrangement is as shown in the attached figure. We have to find the equivalent resistance between any two corner.

It is clear that, resistors R₁ and R₂ are in series. Their equivalent resistances will be :

$R_s=4\ \Omega$

Now resistors R₃ and R_s are in parallel with each other. Their equivalent will be :

$\dfrac{1}{R_{eq}}=\dfrac{1}{4}+\dfrac{1}{2}$

${R_{eq}=1.34\ \Omega$

So, the equivalent resistance between any two corner is 1.34 ohms.