Question

Three 2 Ω resistors are connected as shown in the figure below. ​

Answer 1

Answer:

yes but what's the question?

Answer 2

Answer:

Three 2Ω resistors, A, B and C, are connected as shown in Figure. Each of them dissipates energy and can withstand a maximum power of 18 W without melting. Find the maximum current that can flow through the three resistors.

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Solution

Hint- Use the formula for power decipated in a resistor in terms of current

Step 1 : Finding maximum current flowing through A.

Given: Maximum power each resistor can withstand is 18 W

We know that P = I

2

×R

Where P - Power , I - Current , R - Resistance

Putting the value of P and R

18 = I

2

×2

I

2

= 9

I = 3

This is maximum value of current passing through A.

Step 2 : Finding maximum current flowing through B and C.

As resistance B and C are equal so current I will get equally distributed in B and C

So maximum current in B and C is 1.5 A

Final Step-

Maximum current that can flow through A is 3 A

Maximum current that will flow through B and C is 1.5 A

Explanation:

I hope you understand and it will be help you ❤️