Three 250W heaters are connected in parallel to the 100V supply. Find the energy supplied in kwh by the three heaters in 5 hours
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using formuls , p=250w and potential difference is 100v
so energy supplied by three heater
is p×T
total power =750w= 0.75 kw
time = 5h
Energy = 0.75 ×5= 3.75 KWH
Answered by
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Answer:
using formuls , p=250w and potential difference is 100v
so energy supplied by three heater
is p×T
total power =750w= 0.75 kw
time = 5h
Energy = 0.75 ×5= 3.75 KWH
Explanation:
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