Three 2ohm resistors A,B and C are connected in such a way that B and C are connected in parllel whose combination is connected in series with A. Each of them dissipates energy and can withstand a maximum power of 18W without melting. Find the Maxwell current that can flow through the three resistors.
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Power dissipated by the resistor of 2 ohm (P) = i2R (where i is the current through the resistor and R is the resistance of the resistor.)
Therefore: i2 = P/R =(18/2) A = 9A
⇒ i= 3A
Resistances B and C are connected in parallel, therefore, the current is equally divided in between them i.e. 1.5A
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