Question

Three 6ohm resistors are connected in parallel across 12 volt battery calculate the current flowing in the circuit

Answer 1

As three resistor are connected in parallel therefor "1/R net=1/R1 +1/R2+1/R3".........1/R net=1/6+1/6+1/6

1/Rnet=3/6

1/Rnet=1/2

Rnet=2

As v=12 and Rnet=2

So as we know that V=IRnet

I=V/Rnet

I=12/2

I=6

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