Math, asked by buse7le, 1 month ago

three adults and five children are seated randomly in a row. in how many ways can this be done?

Answers

Answered by amytess12
0

Answer: 8

Explanation: In how many ways can this be done if the three adults are seated together and the five children are also seated together. There are 8! ways of arranging 8 people in a row.

Answered by megha466
0

Answer:

40320 ways they can be seated.

Step-by-step explanation:

three adults and five children are seated randomly in a row. Then the total number of persons are 8 . then the total 8 members can be seated in a row randomly in 8! ways i.e 40320 ways

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