three angle are supplymentry one angle is 40 and other angle are x and y . X and Y are in ratio 2:3 .find the angle .
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if the angles are supplementary their total shall be 180
so angle A = 40
angle B = 2x
angle C = 3x
A + B + C = 180
40 + 2x + 3x = 180
5x = 140
x = 28
angle b = 2 × 28 = 56
angle c = 3 ×28 = 84
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let the measure of angle x and y is m
2m+3m+40°=180°
5m+40°=180°
5m=180°-40°
5m=140°
m=140°÷5
m=28°
x=2m
x= 2*28
x=56°
y=3m
y=3*28
y=84°
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