Question

Three angles form a straight line. The second angle is thrice the first angle. The third angle is five degrees more than the second angle. Find the measure of each angles. pls help me with dis question pls >3

Answer 1

Answer:

let us a triangle ABC .

Let A = x (first angle)

And we have given ,

B = twice of first angle.

B = 2x. (second angle)

C = 40 less than the first angle.

C = x - 40. (third angle)

By using angle sum property we can find the three angles.

A + B + C = 180 .

x + 2x + x - 40 = 180.

4x - 40 = 180.

4x = 180+40.

x = 220/4.

x = 55.

So we have ..

A = 55.

B = 2*55 = 110.

C = 55–40 = 15.