Question

three angles of a quadlateral are in the ratio 2:6:4 . the difference of the least and the greatest of angles out of these angles is the fourth angle. Find all the angles of the quadlateral.​

Answer 1

Answer:

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Step-by-step explanation:

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Answer 2

Answer:

${\huge{\red{\underline{\underline{Question}}}}}$

• Three angles of a quadlateral are in the ratio 2:6:4 . the difference of the least and the greatest of angles out of these angles is the fourth angle. Find all the angles of the quadlateral.

${\huge{\red{\underline{\underline{Theory\ Used}}}}}$

• Sum of all angles of a quadrilateral is 360°

${\huge{\red{\underline{\underline{Answer}}}}}$

${\pink{\underline{\underline{Given}}}}$

Three angles of a quadrilateral in ratio 2:6:4

so, Let the three angles be 2x,6x and 4x

According to given conditions,

Greatest angle-Least angle=Fourth angle

=>6x-2x=Fourth angle

=>Fourth angle=4x

${\pink{\underline{\underline{To\ find}}}}$

Measure of all the angles of a quadrilateral =?????

${\pink{\underline{\underline{Solution}}}}$

Here,1st angle=2x

2nd angle=6x

3rd angle=4x

4th angle=4x

A/Q

1st angle +2nd angle+3rd angle+4th angle=360°

(Sum of all angles of a quad. is 360°)

=>2x+6x+4x+4x=360°

=>16x=360°

=>x=$\frac{360}{16}$

=>x=22.5

Hence,

• 1st angle=2x=2×22.5=45°
• 2nd angle=6x=6×22.5=135°
• 3rd angle=4x=4×22.5=90°
• 4th angle=4x=4×22.5=90°